2007-03-11 20:15:54 · 5 answers · asked by johnson o 1 in Science & Mathematics ➔ Chemistry
First you derive the atomic mass for the compound Cu2S. The atomic mass of copper 63.5 is while that of sulphur is 32 making the atomic mass of the compound: 63.5*2 + 32=159
Therefore the percentage of sulphur is = (32/159) *100=20.125%
2007-03-12 02:20:16 · answer #1 · answered by Samuel_007 2 · 0⤊ 0⤋
Copper I Sulfide
2016-10-14 11:07:48 · answer #2 · answered by aispuro 4 · 0⤊ 0⤋
If you mean percentage by mass, look up atomic mass of Cu and molecular mass of Cu2S then divide the AM of Cu by the MM of Cu2S.
2007-03-11 20:20:24 · answer #3 · answered by gp4rts 7 · 0⤊ 0⤋
Percentage = (Atomic mass of S in Cu2S/ Molecular mass of Cu2S) x100 %
I let someone else do the maths!!!!!!
2007-03-11 20:19:19 · answer #4 · answered by Mr Hex Vision 7 · 0⤊ 0⤋
33%
There are 2 parts Copper to every 1 part Sulfer. Three parts total. 1 of three are sulfer... 1/3 = .3333333 or 33%
2007-03-11 20:24:09 · answer #5 · answered by Chris 2 · 0⤊ 1⤋