Solving Systems of equations?

Question

Can someone show me how to solve this please? the two equations are 6x - 3y - 4 = 0 and x + 2y - 4 = 0 Thanks

Answer 1

6x - 3y - 4 = 0
x + 2y - 4 = 0

First, put both equations in the form ax + by = c.

6x - 3y = 4
x + 2y = 4

Now, solve this; we can use either elimination or substitution. I'll choose substitution (since x is easy to isolate in the second equation).

x + 2y = 4, so x = 4 - 2y. Plugging this into the first equation,

6(4 - 2y) - 3y = 4
24 - 12y - 3y = 4
24 - 15y = 4

-15y = -20
y = 20/15 = 4/3

This means x = 4 - 2y = 4 - 2(4/3) = 4 - 8/3 = 4/3

x = 4/3, y = 4/3

Answer 2

i am guessing you are trying to find what x and y are, right?
ok, so i am going to use linear combination to do this.
you put one on top of the other like this:
6x-3y-4=0
x +2y-4=0
then you have to get either the x's or the y's to cancel out and i am going to have the x's cancel out by multiplying the bottom equation by -6. and then you get:
6x-3y-4=0
-6x-12y+24=0
and now you literlly add the 2 equations together like this:
6x - 3y - 4 =0
-6x-12y+24=0
----------------------
0x-15y+20=0
so then you get y alone on the left side:
-15y=-20
then solve for y and get:
y=4/3
then you plug y=4/3 into one of the original equations. i chose to plug it into x +2y-4=0 and did this:
x+2(4/3)-4=0
so then:
x+(8/3)-4=0
then:
x-(4/3)=0
then:
x=4/3
so in the end you get x=4/3 and y=4/3

i hope this helps you better understand how to solve systems of equations.

Answer 3

Solve for "x =" in equation two.

x+2y-4=0 =====> x = 4 - 2y

"put" this value of x into equation one.
6 x - 3y - 4 = 0
6 ( 4- 2y ) - 3y - 4 =0
24-12y-3y-4=0
-15y +20 = 0
y= 20/15 =====> reduce y=4/3.

Solve for x value: x=4 - 2 (4/3) = 4 - 8/3 = 4/3

ANSWER (4/3 , 4/3)

Answer 4

6x - 3y -4 =0
x + 2y -4 =0

(6x -3y =4 ) x 2
( x +2y =4 ) x 3

12x - 6y =8 ------------>equation 1
3x + 6y=12 ------------->equation 2

By adding equations 1 and 2 we get,

12x - 6y = 8
3x + 6y = 12
15x +0 =20
15x = 20
x = 20/15
x =4/3

By substituting x in equation 1 we get,

3(4/3) +6y = 12

12/3 +6y = 12
12 +18y /3 = 12
12 + 18y =36
18y =36 - 12
18y = 24
y = 24/18
y = 4/3

Therefore, x = 4/3
y = 4/3

Answer 5

5x + 2y = 15 -5x - 2y = -5 _____________ 0 = 10 you clean up using combining words, you upload the two equations. 0=10 ability this methodology of equation has no answer in any respect, because of the fact the slopes of the two traces are the comparable, in different words are parallel traces, so there is not factor of interception

Answer 6

first make coefficients of x to be same in both eqn
multiply2nd eqn by 6 it becomes 6x+12y-24=0
then subtract both eqn
you get 15y=20
hence y=1.33 substitute it in eqn 1 you get x=1.333