English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2 answers

For traditional bulbs, there is a correlation between higher luminosity (measured in lumens) and power.

Power is defined as I(current)*V(Voltage), or also:

I^2*Resistance.

Since the voltage is the same for all bulbs, then we know their current must be greater. In fact, by reducing the resistance, we are increasing the current, or amperage (amps).

So a bulb that burns brighter uses more power, and therefore has lower resistance.

2007-03-11 19:15:06 · answer #1 · answered by bloggerdude2005 5 · 0 0

^^^^that guy is absolutely 100% WRONG

it turns out wires with HIGHER resistance are better at conducting heat and light. They allow the passage of electrons and complete the circuit as conductors, but not easily. BECAUSE of their high resistance, the charge carriers that pass through the wire have a higher chance of bumping into the nuclei of the wire's atoms. This bumping causes friction and KE, which results in the wire giving off heat and light. If I were to wire a spotlight, I would use a high resistance wire for the filiment, so it would produce heat and light.

2007-03-12 04:04:16 · answer #2 · answered by tom h 3 · 0 0

fedest.com, questions and answers