(x-2)(x-8)=0
X^2+16-10x =0
form a question as chanllenging as possible.
2007-03-11 17:33:26 · 3 answers · asked by stefanythequeenie 1 in Science & Mathematics ➔ Mathematics
(x-2)inch is the length of the base of an right-angled triangle and (x-8)inch is the height of the triangle. Find the area of the triangle in sq feet.
2007-03-11 17:36:41 · answer #1 · answered by math freak 3 · 0⤊ 1⤋
math freak's problem doesn't make sense because the area of a triangle can't be 0.
I would just say that a particle varied motion with time with the equation x(t)=t^2+16-10t. and the question is, at what time, t, is the particle at 0?
2007-03-12 00:42:42 · answer #2 · answered by tobysamples 1 · 1⤊ 0⤋
A square is given with side length equal to x. A rectangle has side lengths 2 and 5x-8. The areas of the rectangle and square are equal. Find x.
2007-03-12 00:40:03 · answer #3 · answered by mitch w 2 · 0⤊ 0⤋