(6a^2/7b^3)^-2 simplify!
2007-03-11 17:21:56 · 4 answers · asked by Tami R 2 in Science & Mathematics ➔ Mathematics
(6a^2/7b^3)^-2
= (7b^3/6a^2)^2
= [(7)^2 (b^3)^2] / [(6)^2 (a^2)^2]
= 49b^6 / 36a^4
2007-03-11 17:26:24 · answer #1 · answered by seah 7 · 1⤊ 0⤋
The reciprocal rule tell us this is equal to
(7b^3 / 6 a^2) ^2, so we proceed to square both the num and den of the fraction:
49b^6 / 36 a^4
Since b and a only occur once, the variables can't be simplified, and since 49 and 36 have no common integer factors, the coefficients can't be simplified. So that all, folks!
2007-03-12 00:30:42 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
(6a² / 7b³)-² =
(7²b³)² / (6²a²)² =
49b^6 / 36a^4
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2007-03-12 00:28:13 · answer #3 · answered by aeiou 7 · 0⤊ 0⤋
49b^6/36a^4
HTH âº
Doug
2007-03-12 00:25:54 · answer #4 · answered by doug_donaghue 7 · 0⤊ 0⤋