A container of gas is at a pressure of 3.7 x 10^5 Pa.?

Question

How much work is done by the gas if it's volume expands by 1.6 m^3?
please show me how to do this calculation, thanks

Answer 1

Assuming this is a well insulated piston the work done is simply

dW=p*dV and if we assume pressure is constant
then we have dW=p*dV
which in this case is 3.7E5*1.6=592 kJ

But if pressure changes
under the ideal gas law pV=nRT so as a function of V
dW=nRT/V dV
because T is constant, we integrate over an isotherm from V1 to V2

W=nRT*ln(V2/V1)