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what is the temperature change of 100.0 ml of water when it absorbs 1365 joules of heat?

2007-03-11 17:01:53 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

The answer is still given by
rerranging the formula
q = mcdt.

c is always 4.18 for water
if given mL of water, 1 mL = 1 g or 1 L = 1000 g = 1kg

Time for you to make an effort with these questions - they are all the same

2007-03-11 17:07:29 · answer #1 · answered by Anonymous · 0 0

delta T = 1365/(4.184* 100) = 3.26 degrees C

2007-03-11 17:10:09 · answer #2 · answered by TheOnlyBeldin 7 · 0 0

1365J=0.100kg(h2o)* 4.18(J/(kg*K)) * T

therefore T=1365/(.1*4.18)

2007-03-11 17:10:53 · answer #3 · answered by tobysamples 1 · 0 0

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