How do you solve a q=mcdeltat problem?

Question

how much heat is raised when 275 grams of water cools from 85.2 degrees C to 38.4 degrees C?

Answer 1

Q=mcdeltaT c for water= 1 cal/C.g
Q=275g * 1cal /C.g * (85.2 - 38.4 )
= 275 * 1 * 46.8 C
=12870 cal
=12.870 kcal

Answer 2

I presume that the questioner means ''heat released'' rather than heat raised.
The answer can be found out as follows,
q=275 X 1 X (85.2 - 38.4)=12870 calories=12.87 Kcal.