How many squares will be bought to cover the floor?
2007-03-11 15:55:53 · 6 answers · asked by hailey 1 in Science & Mathematics ➔ Mathematics
12 FT X 8 INCHES = 1 tile wide
144/8 = 18
18 tiles
2007-03-11 15:59:24 · answer #1 · answered by tom4bucs 7 · 0⤊ 0⤋
Since the tiles are 8-inches square and the room is 8 inches wide ( are you sure it is not 8 feet wide?) the all you have to do is compute how many 8 inches are in 12 feet.
12 feet / (8inches/12 inches per foot)
144/8 = 18 tiles.
If the room is really 12 ft x 8 ft. The total area is
96 square feet.
Each 8-inch tile is (8/12)^2 =0.444 square feet
Divide 96 square feet by 0.444 square feet,
and you get 216 tiles
2007-03-11 23:10:52 · answer #2 · answered by kale_ewart 5 · 0⤊ 0⤋
Do you really mean 8" wide? if so, 12'=144"
144"/8"/tile=18 tiles. If you meant 12' by 12' then
144"*96"= 13824 in^2
each tile is 8"*8"=64 in^2
13824 in^2/64 in^2/tile=216 tiles
2007-03-11 23:19:47 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
The area of the floor is 144 inches (I assume you have it typed correct) * 8 inches = 1152 square inches.
An 8 inch tile is 64 square inches.
1152/64 = 18 tiles
2007-03-11 23:01:27 · answer #4 · answered by Jeff U 4 · 0⤊ 0⤋
Your measurements are off, no floor is 12 feet by 8 inches wide as your question says.
2007-03-11 23:02:16 · answer #5 · answered by JAN 7 · 0⤊ 0⤋
216 to be exact but order extra so you have extras for cut tiles and all that and im guessin u meant 12ft by 8 ft
2007-03-11 23:02:43 · answer #6 · answered by b 2 · 0⤊ 0⤋