11x^2-32x-3
sorry, but i really need some help here...
2007-03-11 15:48:36 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
First, set up your parentheses:
(11x + )(x - ) = 0
Next, find two factors of -3 that when multiplied with 11 and 1, their products added together will equal -32.
Therefore:
(11x + 1)(x - 3) = 0
Set both factors to zero and solve.
11x + 1 = 0
11x = -1
x = -1/11
and
x - 3 = 0
x = 3
2007-03-11 15:51:02 · answer #1 · answered by sillyboys_trucksare4girls 2 · 0⤊ 0⤋
11x^2 - 32x - 3 =0
(11x + 1)(x - 3) = 0
11x + 1 = 0
11x = -1
x = -1/11
or
x - 3 =0
x = 3
2007-03-11 22:55:59 · answer #2 · answered by Johnny Handsome 2 · 0⤊ 0⤋
Hepl doing what? Do you want it factored?
11x^2-32x-3=0
(11x+1)(x-3)
2007-03-11 22:52:13 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
(11x+1)(x-3)
2007-03-11 22:52:03 · answer #4 · answered by ecolink 7 · 0⤊ 0⤋