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16 - 9/16m^2


how do i do this?

2007-03-11 15:32:12 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

Do what?

If you mean factor and you meant that it is 16 -(9/16) m^2 then it is the differenct of two squares. [4 - (3/4) m]*[4 + (3/4) m]

2007-03-11 15:35:16 · answer #1 · answered by PZ 4 · 0 0

You want to factorise this? Its not binomial, or at least I don't see how the term "binomial" and what you wrote to be in anyway, connected.

Anyway, to factorise the expression you wrote, here is how you do it.

16 -9/16m^2 =
4^2 - (3/4m)^2 =
(4 + 3/4m) ( 4 - 3/4m)

2007-03-11 15:37:18 · answer #2 · answered by ali 6 · 0 0

To factor this, it's the difference of two squares (because 9/16 m^2 is (3/4 m)squared)

(4 + 3/4m)(4-3/4m)

2007-03-11 15:35:28 · answer #3 · answered by ecolink 7 · 0 0

Is this a factoring problem? If it is, remember that a^2 - b^2 = (a + b) (a - b).

In this case a = 4 and b = 3/4m. So the answer is

(4 + 3/4m) (4 - 3/4m)

2007-03-11 15:36:52 · answer #4 · answered by Anonymous · 0 0

It's a difference of squares

a^2 - b^2 = (a-b)(a+b)
here a = 4 and b = 3/(4m)

(4-3/(4m))(4+3/(4m))

2007-03-11 15:36:22 · answer #5 · answered by radne0 5 · 0 0

16-(9/16m^2)???
What will you do? simplify or factor?
a.) if you want to simplify:
[16(16)m^2-9]/16m^2 = (256m^2-9)/16m^2
b.) if you want to factor:
[4-3/4m]x[4+3/4m]
hope you understand..
God bless!!!!

2007-03-11 15:41:38 · answer #6 · answered by geloi 2 · 0 0

factor

2007-03-11 15:35:11 · answer #7 · answered by layla 3 · 0 0

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