Can You HELP!!?

Question

The perimeter of a rectangle is 78. The length of the rectangle is 6 inches more than the width. Find the rectangle's length and width. I also want to know how you got the answer.

PLEEZ DON'T SAY 'DO YOUR OWN HOMEWORK!!'

Answer 1

Start by writing out the equations that are given in the problem. Since it's a rectangle, two sides will be of equal length and the other two sides with be of another equal length. 2x + 2y = 78. The second equation is given as x = y + 6. You can use the second equation to substitute for x in the first equation and find y, then plug your answer for y to find the lengths of each side.

Answer 2

Here's a hint. You're supposed to use algebra.

Rectangles have 4 sides, two of one length and two of another. The perimeter is the sum of the lengths of the four sides. So if I has to sides of length a, and two of length b, the perimeter = 2*a + 2*b. Good so far?

You also know that the length is the width plus 6 inches, or a = b+6. So you have an equation for a. Plug in your equation for a into your first equation and solve for b, then plug b back into your second equation to solve for a.

Answer 3

L = length, w = width
w+6=L
2L +2w = 78
2w+2(w+6) = 78
2w + 2w + 12 =78
4w = 78 – 12
w = 66/4
w = 16 ½
L = 16 ½ + 6 = 22 ½

Answer 4

the width is 16.5 and the length is 22.5

here's how to find it if you care:


to find the width:
let w=width.
2w+2(w+6)=78
2w+2w+12=78
4w=66
w=16.5 (or 16 1/2)

to find the length:
width +6
16.5+ 6
length = 22.5 (or 22 1/2)

Answer 5

6 + w times h+78
-6 +6 +w times h = 78 -6
w times h = 72
8 times 9 = 72

Hope this helps

Answer 6

22.5 and 16.5


i did trial and error. i started with 26 and 20... then 25 and 19... and worked backwards...