I would. You think he is better than McCain?
2007-03-11 15:00:45
·
answer #1
·
answered by Anonymous
·
1⤊
0⤋
He IS going to run, will announce tomorrow (3/12) according to Chris Matthews.
I'm a Democrat, and there is NO Republican I would vote for... except Hagel. If Clinton is the Dem nominee, and Hagel the Repub, Hagel probably gets my vote. And I'm a liberal.
So yeah, I think you're right.
2007-03-11 15:00:25
·
answer #2
·
answered by Anonymous
·
2⤊
0⤋
How do you figure Hagel would be like running Hillary against Hillary or Obama against Obama.
No I would support him if he runs there are too many other good ones out that should run.
Maybe talk Robin Williams in running I would support that over Hagel.
2007-03-11 15:00:33
·
answer #3
·
answered by Anonymous
·
2⤊
1⤋
interior the present occasion ecosystem, the Republicans could desire to opt for somebody who will charm to the two events, yet with an emphasis on the moderates; that guy or woman is in all probability Giuliani. no longer in basic terms does he have the useful "call acceptance" ingredient, a number of his politics will charm to the two moderates and liberals besides as conservatives.
2016-10-01 23:26:36
·
answer #4
·
answered by ? 4
·
0⤊
0⤋
No, I'm already rooting for Edwards.
However, I like him a lot more then bush and hope he wins the primaries, that way if the Reps win in 08 it won't be so bad for me (and every other American)
2007-03-11 15:00:41
·
answer #5
·
answered by The Big Box 6
·
1⤊
0⤋
No way. This guy is an idiot. An opportunistic idiot.
I hope he runs, gets the nomination and has to give up being a Senator, and then gets defeated. Then we would be shut of his sorry a**!
2007-03-11 15:36:17
·
answer #6
·
answered by plezurgui 6
·
0⤊
2⤋
is he born-again,, if not,, you can subtract 27% of the Republican voters,,, the RNC are scrapping the bottom of the barrel with Rudy,,, he is pro choice,, pro abortion,, pro gun control,,, but conservative values,, they ain't what they use to be,,,,
2007-03-11 15:36:10
·
answer #7
·
answered by Anonymous
·
0⤊
2⤋