2007-03-11 14:47:59 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
This is a simple difference of squares. The general formula for such a problem is:
a^2 - b^2 = (a + b)(a - b)
Therefore in this case:
9 - x^2 = (sqrt9 + sqrtx^2)(sqrt9 - sqrtx^2) = (3 + x)(3 - x)
2007-03-11 14:51:19 · answer #1 · answered by Tim 4 · 0⤊ 0⤋
If you have a^2 - b^2 then it factors into (a+b)(a-b), so 9-x^2 factors into (3+x)(3-x)
2007-03-11 21:50:38 · answer #2 · answered by Anonymous · 0⤊ 0⤋
This is of the form a^2-b^2 = (a+b)(a-b)
So the answer is 3^2-x^2 = (3+x)(3-x)
2007-03-11 21:50:42 · answer #3 · answered by astatine 5 · 0⤊ 0⤋
this is the most simple of factorizations. if you don't know this, there is no point having someone do it for you. You must either not be going to class, or paying attention or doing your homework. You must get help right away or school will only get worse. It will catch up with you. See the teacher.
2007-03-11 21:54:31 · answer #4 · answered by Rick 5 · 0⤊ 1⤋
First, move the -x^2 to the other side to make it positive:
x^2 = 9
Then, find the square root of both sides:
x = +/- 3
2007-03-11 21:49:56 · answer #5 · answered by sillyboys_trucksare4girls 2 · 0⤊ 0⤋
It's the difference of two squares.
(3+x)(3-x)
2007-03-11 21:50:23 · answer #6 · answered by ecolink 7 · 0⤊ 0⤋