were suppose to multiply. I got 6x + 5 + 6x + 5. Is that right or am I doing something wrong?
2007-03-11 13:54:46 · 13 answers · asked by gizzie76 1 in Science & Mathematics ➔ Mathematics
4x^2+6x+6x+9 = 4x^2+12x+9; you use FOIL
2007-03-11 13:57:24 · answer #1 · answered by stylistikal 3 · 0⤊ 0⤋
Multiply through:
(2x)(2x) + 3(2x) + 2x(3) + 9 =
4x^2 + 6x + 6x + 9 =
4x^2 + 12x + 9
2007-03-11 14:03:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Use foil
4x^2 + 6x + 6x + 9 = 4x^2 + 12x + 9
2007-03-11 13:57:46 · answer #3 · answered by richardwptljc 6 · 0⤊ 0⤋
You do:
(2x+3)(2x+3)
(2x)(2x)+(3)(2x)+(3)(2x)+(3)(3)
4x^2+6x+6x+9
4x^2+12x+9
I got this by using the FOIL method. When using FOIL with an equation like this (Ax+B)(Cx+D) you have to multiply the "Ax" to everything in the other set of paraenthesis and you do the same with the "B". So basically the answer is the simplified version of (Ax)(Cx)+(Ax)(D)+(B)(Cx)+(B)(D ). I hope this helps you in understanding how to use the FOIL method and I hope you understand how I completed the problem correctly.
2007-03-11 14:17:12 · answer #4 · answered by badgers11081 2 · 0⤊ 0⤋
(2x)^2 + 6x + 6x + 9 = (2x)^2 +12x + 9
2007-03-11 14:06:45 · answer #5 · answered by =D 2 · 0⤊ 0⤋
4x^2 + 12x + 9
2007-03-11 14:01:20 · answer #6 · answered by Gardenia 6 · 0⤊ 0⤋
Use FOIL (first, outer, inner, last) to multiply this out.
You'll come up with:
4x^2 + 12x + 9
2007-03-11 13:59:30 · answer #7 · answered by Mystery Viscera 2 · 0⤊ 0⤋
its 6
2007-03-11 14:02:44 · answer #8 · answered by Wayne M 1 · 0⤊ 0⤋
4x squared + 12x + 9
2007-03-11 14:00:02 · answer #9 · answered by i <<<3 music 1 · 0⤊ 0⤋
FOIL it. Multiply:
First terms of each parenthesis. 2x*2x = 4x^2
Outer terms of each paren. 2x*3 = 6x
Inner terms of each paren. 3*2x = 6x
Last terms of each paren. 3*3 = 9
Put them all together:
4x^2 + 12x + 9 is the answer.
2007-03-11 13:59:41 · answer #10 · answered by ecolink 7 · 0⤊ 0⤋