The national touring company of Sesame Street Live visited Seattle, Washington, last year. The
producers held a special promotional ticket sale for one hour. During this time, adult tickets sold for $5,
junior tickets (kids aged 8 to 16) sold for $2, and children's tickets (kids aged 0 to 8) sold for the
ridiculously low price of 10 cents. During this sale, 120 tickets sold for exactly $120. How many of each
kind of ticket were sold during the sale?
2007-03-11 13:52:56 · 2 answers · asked by lilprincess_2good4u 1 in Science & Mathematics ➔ Mathematics
Let A, J, C be the number of tickets for each type.
A+J+C=120 (ticket sales)
5A+2J+0.1C= 120 ( proceeds)
10 mod C =0 (C is a multiple of 10 since proceeds are an even dollar amount)
A, J and C are integers
Pick a C, enter into eqtn and see when the other conditions are met.
A=17, C=90, J=13
2007-03-11 14:14:45 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
x = # of adult tickets
y = # of junior tickets
z = # of children's tickets
Then x+y+z=120
5x +2y +.1z = 120
So we have three unkowns and only two equations. This could mean that there is more than one solution or, that there is no solution.
By trial and error we find
x = 17 adult tickets
y= 13 junior tickets
z = 90 children's tickets
2007-03-11 21:33:26 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋