let f(x)=1/(x+3) and g(x)=8x/(x+3), find f(x)/g(x)?

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let f(x)=1/(x+3) and g(x)=8x/(x+3), find f(x)/g(x)?

2007-03-11 13:50:43 · 4 answers · asked by mohammed 1 in Science & Mathematics ➔ Mathematics

4 answers

1) (1/x+3)/(8x/x+3)
2) (1/x+3) * (x+3/8x) when dividing,flip the sigh to multiplying
3) (x+3)/(8x^2+24x)
4) (x+3)/8x(x+3) factor the denominator
5) 1/8x

2007-03-11 13:59:50 · answer #1 · answered by Gardenia 6 · 0⤊ 0⤋

1/(x+3) times (x+3)/8x = 1/8x

2007-03-11 20:53:53 · answer #2 · answered by richardwptljc 6 · 0⤊ 0⤋

Multiply by reciprocal, cancel (x+3)

1/8x

2007-03-11 20:53:45 · answer #3 · answered by Mogli of the Jungle 2 · 0⤊ 0⤋

1/(x+3) / 8x/(x+3) = 1/(x+3)*(x+3)/8x
= 1/8x

2007-03-11 20:54:36 · answer #4 · answered by ecolink 7 · 0⤊ 0⤋