Were suppose to multiply. I got x to the eighth power - x to the eighth power. I don't think that's right could someone tell me. Thanks.
2007-03-11 13:45:36 · 12 answers · asked by Shelby B 1 in Science & Mathematics ➔ Mathematics
x^2-64
In general, (a-b)(a+b)=a^2-b^2
2007-03-11 13:49:16 · answer #1 · answered by ironduke8159 7 · 2⤊ 0⤋
It's not. These questions always follow a pattern-usually, though, I've been asked to find this from the probelm you're looking for.
All right. Here's the steps.
1. In each grouping, multiply the first numbers. Here, those are x and x. x times x =x^2.
2. Multiply the first number of the first grouping to the last number of the second. x times 8= 8x. So far, we have x^2+8x.
3. Multiply the second number of the first grouping by the first number of the second. -8 times x= -8x. So, x^2+8x-8x
4. Multiply the last numbers of each grouping. -8 times 8 = -64. So, x^2+8x-8x-64
5. Simplify. Right in the middle, you have 8x minus 8x. So, the answer is x^2-64.
Hope that helps.
2007-03-11 20:59:22 · answer #2 · answered by dark_load1 2 · 0⤊ 0⤋
Simply put, you mulitply the x in the first pair into the second pair:
x^2 + 8x
Then you multiply the -8 from the first pair into the second pair:
-8x - 64
Finally, you add them together and combine like terms:
x^2 + 8x - 8x - 64 = x^2 - 64
2007-03-11 20:48:09 · answer #3 · answered by Dave 6 · 1⤊ 1⤋
Study remarkable products
(x-8)(x+8) = (x² - 8²) = x² - 64
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2007-03-11 21:24:59 · answer #4 · answered by aeiou 7 · 0⤊ 0⤋
it means multiply each term of left factor by each term of right factor
xx +8x -8x -8*8 = x^2 - 64
2007-03-11 20:48:50 · answer #5 · answered by hustolemyname 6 · 2⤊ 0⤋
No, you use the FOIL method. First, outer, inner, last.
First:
Multiply the first two factors of each parenthesis.
(x)(x)
x^2
Outer:
Multiply the the two outer factors of each parenthesis.
(x)(8)
8x
Inner:
Multiply the two inner factors of the parenthesis.
(-8)(x)
-8x
Last:
Multiply the two last factors of the parenthesis.
(-8)(8)
-64
Now, put it together.
x^2+8x-8x-64
The +8x and -8x eliminate each other, so the answer is:
x^2-64
2007-03-11 20:57:44 · answer #6 · answered by true_wahoo 3 · 0⤊ 0⤋
It's x^2 - 64.
This is the "difference of two squares".
2007-03-11 20:48:40 · answer #7 · answered by ecolink 7 · 2⤊ 0⤋
using the foil method
x^2+8x-8x+64
x^2+64
so its x^2+64.
2007-03-12 10:45:12 · answer #8 · answered by Gonzo 1 · 0⤊ 0⤋
(x-8)(x+8) =
x^2 -8x+8x-64=
x^2-64
2007-03-11 20:49:16 · answer #9 · answered by jaybee 4 · 2⤊ 0⤋
Using the FOIL method it becomes:
x^2 - 8x + 8x - 64
Then, your - 8x and + 8x cancel each other out. This leaves you with:
x^2 - 64
Move your 64 to the other side of the equation.
x^2 = 64
Answer:
x = +/- 8
2007-03-11 20:48:17 · answer #10 · answered by sillyboys_trucksare4girls 2 · 1⤊ 4⤋
what is your question?
is it to expand.
then it should be
x^2+64
any problem like this can be figured out in 3 seconds flat,
due to the property that
(a-b)(a+b)=a^2-b^2
2007-03-11 20:50:22 · answer #11 · answered by lcjjr87 2 · 1⤊ 1⤋