What volume of 2.8 M NaHCO3 solution is required to convert 5.0 g of benzoic to sodium benzoate.?

9 ⤊

What volume of 2.8 M NaHCO3 solution is required to convert 5.0 g of benzoic to sodium benzoate.?

2007-03-11 13:23:20 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

NaHCO3 (aq) + C6H5CO2H --> C6H5CO2Na (aq) + H2O (l) + CO2 (g)

The MW of Benzoic acid = 122.12 g/mol.

5.0 g of Benzoic acid / 122.12 g/mol = 0.409 moles

0.409 moles / 2.8 moles/L = 0.0146 L = 14.6 mL

2007-03-11 16:37:54 · answer #1 · answered by Richard 7 · 9⤊ 0⤋

Wow your studying same stuff we are at school,

Do you know how many times the elemt is present in the compounds?

2007-03-13 17:36:46 · answer #2 · answered by akoon 2 · 0⤊ 0⤋