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The electric field everywhere on the surface of a thin spherical shell of radius 0.750 m is measured to be equal to 890 N/C and points radially toward the center of the sphere. What is the net charge with the sphere's surface?

2007-03-11 13:21:47 · 1 answers · asked by Belle 3 in Science & Mathematics Physics

1 answers

E=q/4πεr^2
plugging and solving

890=q/4πε(0.75)^2

q=890*4π*8.85E-12*(0.75)^2=55.7 nC

2007-03-11 16:56:32 · answer #1 · answered by Rob M 4 · 1 0

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