How can two triangles have five parts (angles and sides) of one congruent to five parts of the other and still not be congruent??
2007-03-11 13:18:09 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i think the trick is that the word corresponding isn't there...but i'm not sure...
2007-03-11 13:23:34 · update #1
I think you have the idea. If the two triangles have congruent parts, but in different orders, then they aren't necessarily congruent. You can probably draw a picture like this to prove your point.
2007-03-11 13:27:32 · answer #1 · answered by Dave 6 · 0⤊ 0⤋
I don't think it can be done, at least not in this dimension.
No. This would mean that either 3 sides and 2 angles are congruent and the third pair of angles isn't congruent (this is impossible by the triangle angle sum), or 3 angles and 2 sides are congruent, and the third side isn't congruent (this is impossible also, because when 3 angles and even just one side are fixed, the triangle is determined).
2007-03-11 20:29:47 · answer #2 · answered by Old guy 124 6 · 0⤊ 0⤋
Agree totally with the second person. If the two triangles had sides congruent, then by SSS, the triangles are.
If not, then one of the sides is not given to be congruent, but all three angles are given to be so. Thus one of ASA or SAS criteria will be valid and the triangles will be congruent. So it is not possible to have the triangles to be non-congruent.
2007-03-12 02:51:25 · answer #3 · answered by FedUp 3 · 0⤊ 0⤋