factor these polynomials.
1. 4n3-20n2-9n+45
2. g4+6g3+9g2-3g2h-18gh-27h
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2007-03-11 13:16:41 · 3 answers · asked by vballchick06 2 in Science & Mathematics ➔ Mathematics
1. 4n3-20n2-9n+45
This can be factored by grouping
Factor 4n^2 from the left two terms
Factor -9 from the right two terms
4n^2(n - 5) -9(n - 5)
(4n^2 - 9)(n - 5)
The first binomial is a difference of squares
(2n + 3)(2n - 3)(n - 5)
2. g4+6g3+9g2-3g2h-18gh-27h
Grouping
g^2(g^2 + 6g + 9) -3h(g^2 + 6g + 9)
(g^2 - 3h)(g^2 + 6g + 9)
Factor the trinomial
(g^2 - 3h)(g + 3)(g + 3)
2007-03-11 13:27:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1) 4n^2 (n - 5) - 9 (n - 5)
(4n^2 - 9)(n-5)
(2n + 30(2n - 3) (n - 5)
2) g^2 (g^2 + 6g + 9) -3h (g^2 + 6g + 9)
(g^2 + 6g + 9)((g^2 - 3h)
(g + 3)(g+3)(g^2 - 3h)
2007-03-11 13:23:47 · answer #2 · answered by richardwptljc 6 · 0⤊ 0⤋
I'm assuming that you mean squared and cubed so...
1. 4n^2(n-5)-9(n-5)
sorry, my brain hurts now, hope I helped
2007-03-11 13:24:54 · answer #3 · answered by Jennifer W 2 · 0⤊ 0⤋