Solve. (The operation is sutraction.) [(x + 5)/3] - [(x - 1)/2] = 1
2007-03-11 13:06:49 · 7 answers · asked by steph158_4 1 in Science & Mathematics ➔ Mathematics
The minus sign changes the signs of the numbers in the bracket.
(x + 5)/3 - (x - 1)/2 = 1 Multiply both sides by 6.
2x + 10 - 3x + 3 = 6 Get x by itself.
-x = -7
x = 7
2007-03-11 13:11:39 · answer #1 · answered by ecolink 7 · 1⤊ 0⤋
Try a standard fraction attack (sounds good, eh?). Multiply everything by (3x2) = 6. So 6[(x+5)/3] - 6[(x-1)/2] = 6. Now do some cancellation and get 2[(x+5)] - 3[(x-1)] = 6. That is now an easy problem to solve. Just had to either get everything over the same denominator, or as in this case, get rid of the denominators all together.
2007-03-11 13:21:06 · answer #2 · answered by ZORCH 6 · 0⤊ 0⤋
put both fractions over the same denominator (6)
by multiplying the terms by 2 and three respectively to get
[2(x+5) - 3(x-1)]/6 = 1
multiply both sides by 6
2(x+5) - 3(x-1) = 6
multiply out the brackets
2x+10 - 3x +3 = 6
simplify
13-x = 6
rearrange to find x
(13-6) = x x = 7
2007-03-11 13:13:55 · answer #3 · answered by rg 3 · 0⤊ 0⤋
Multiply through by the lowest common denominator of 3 and 2, which is 6, to get
2(x + 5) - 3(x - 1) = 6
(2x + 10) - (3x - 3) = 6
2x + 10 - 3x - -3 = 6
2x + 10 - 3x + 3 = 6
13 - x = 6
7 = x
2007-03-11 13:11:59 · answer #4 · answered by ymail493 5 · 0⤊ 0⤋
x/3 + 5/3 - x/2 + 1/2 = -x/6+13/6 =1
-x + 13 = 6
x =7
2007-03-11 13:12:10 · answer #5 · answered by hustolemyname 6 · 0⤊ 0⤋
Multiply all terms by 6,. then
2(x+5) - 3(x-1) = 6
expand...
2x + 10 - 3x +3 = 6
-x +13 = 6
x= 7 :)
2007-03-11 13:12:26 · answer #6 · answered by Anonymous · 0⤊ 0⤋
x=7
Please give me best answer thanks!
2007-03-11 13:18:47 · answer #7 · answered by Anonymous · 0⤊ 0⤋