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2 answers

5A = 3 unpaired
2A = 0 unpaired
6A = 2 unpaired
8A = 0 unpaired

2007-03-11 12:05:50 · answer #1 · answered by physandchemteach 7 · 0 0

P has selection 15 so the electron configuration could be 1s(2) 2s(2) 2p(6) 3s(2) 3p (5) We see that the 3p sub shell isn't finished, if we glance into the orbitals, it has 3 orbitals in each and each orbital 2 electrons could properly be cutting-edge. Hund's regulation says which you need to fill an orbital first with electrons of the comparable spin one consistent with orbital till the subshell is done, in basic terms then you definately could upload an electron of opposite spin. So we do this for 3p 2 2 a million is what we get , so the 1st 2 orbitals are finished with paired electrons, and the final orbital has in basic terms one electron. the respond is a million.

2016-12-18 20:19:36 · answer #2 · answered by weissinger 4 · 0 0

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