help with this math prob?

Question

A particle moves on the x-axis so that its position at any time t > or = 0 is given by x(t) = 2te^-2
(A) find the acceleration of the particle at t = 0
(B) find the velocity of the particle when its acceleration is 0
(c) find the total distance traveled by the particle from t = 0 to t = 5.

Answer 1

x(t) = 2te^-2
v(t) = x'(t)
a(t) = v'(t)

x'(t) = 2e^-2 = v(t)
v'(t) = 0 = a(t)

A) 0
B) a = 0 for all t>=0 the velocity for t>0 is 2^-2, for t = 0 it is 0

C) ..\
i think you made a typo ( isnt is e^-2t instead opf e^-2 ? )
uits weird that a particle stops so quickly as yoyu states,

Answer 2

first ans has wrong x' , use product rule