2007-03-11 10:51:31 · 4 answers · asked by Suri T 1 in Science & Mathematics ➔ Mathematics
(5x^2 + 1)(x^2 + 6)
2007-03-11 10:55:06 · answer #1 · answered by Newbody 4 · 1⤊ 0⤋
Let a = x^2, then
5a^2 + 31 a + 6 = (5a+1)(a+6)
Put back in the values of a:
(5x^2+1)(x^2+6)
x^2 + 6 = (x-i sqr[6])(x+i sqr[6])
5x^2 + 1 = (sqr[5]+i)(sqr[5]-i)
2007-03-11 10:57:40 · answer #2 · answered by kellenraid 6 · 1⤊ 0⤋
Letting a = x² is the correct approach.
(5x² + 1)(x² + 6) is your answer.
[Note: The factors cannot be 'solved' because the expression is not an equation.]
2007-03-11 12:07:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the expression is 5[x^4-13x^2+36] =5 [ok^2-13k+36] the place ok=x^2 =5 [ok^2-9k-4k+36] =5[ok(ok-9)-4(ok-9)] =5(ok-9)(ok-4) placed ok=x^2 =5(x^2-9)(x^2-4) now notice x^2-y^2=(x+y)(x-y) =5(x+3)(x-3)(x+2)(x-2) ans
2016-10-18 03:26:50 · answer #4 · answered by cutburth 4 · 0⤊ 0⤋