Can someone help me with this? Find equation of the line that contains the given pair of points (26,28) (7,9)?

Answer 1

Slope = 28 - 9 over 26 - 7 = 19/19 = 1

y = mx+b
9 = 1(7) + b

b = 2

y = x + 2

Answer 2

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Answer 3

use the slope offset
x=slope y +offset

slope is rise over run
x difference is rise, y difference is run

26-7 = 19
28-9 = 19

slope is then 1 (19/19 = 1)
so
x= 1y + offset
or
x=y+ offset

offset is y when x = 0
so solve for y
let offset be a

x =y+a
x-a=y+a-a
x-a=y

then plug in either point

7-a=9
7-7-a=9-7
-a=2
a= -2

so

x=y-2

then check with the points given

26=28-2 is true
7=9-2 is true

all checks are good, so the equasion for the line is

x=y-2

Answer 4

y = x + 2.

Answer 5

First find the slope.

(28 - 9) / (26 - 7) = 19 / 19 = 1

Then find the intercept.

9 = 7 + ?, so ? = 2

The line is y = x + 2.

Answer 6

Slope formula:
m=(y2-y1)/(x2-x1)
m=(9-28)/(7-26)
m=-19/-19=1

Point-slope formula:
y-y1=m(x-x1)
y-28=1(x-26)
y-28=x-26
y=x+2

I hope this helps!