Ok i could do this by grouping
so then it will become 4x^2(2x-3) 1(-2x+3)
is there more to it do i keep on?
2007-03-11 10:10:23 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
one more thing is 3x^4-300x^2 you will get the answer 3x^2(x-25)(x+25)
2007-03-11 10:13:52 · update #1
4x^2(2x-3) -1(2x -3)
(2x -3) (4x^2 -1)
(2x - 3)(2x+1)(2x-1)
2007-03-11 10:13:47 · answer #1 · answered by richardwptljc 6 · 1⤊ 0⤋
factor by groups
(8x^3 - 12x^2) + (-2x + 3)
4x^2 (2x - 3) + -1 (2x - 3)
(4x^2 - 1) (2x - 3)
(2x - 1)(2x + 1) (2x - 3)
3x^4-300x^2
take out the 3x^2
3x^2 (x^2 - 100)
3x^2(x+10)(x-10)
2007-03-11 10:15:07 · answer #2 · answered by 7 · 1⤊ 0⤋
4x^2(2x-3)-1(2x+3)
(4x^2-1)(2x+3)
(2x-1)(2x+1)(2x-3)
Is 3x^4-300x^2 go to 3x^2(x-25)(x+25)?
3x^2(x^2-100)
3x^2(x-10)(x+10)-that's the right answer!
I hope this helps!
2007-03-11 10:20:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋
It is 4x^2(2x-3)-1(2x-3)=(4x^2 - 1)(2x - 3) = (2x - 1)(2x + 1)(2x - 3)
2007-03-11 10:16:50 · answer #4 · answered by Amit Y 5 · 0⤊ 0⤋
4x^2(2x-3) - (2x-3)
= (4x^2-1)(2x-3)
= (2x+1)(2x-1)(2x-3)
2007-03-11 10:14:52 · answer #5 · answered by sahsjing 7 · 1⤊ 0⤋
to factor anythings write that like this: (a1x - b1)(a2x - b2 )...(anx - bn )
the answer of this is:
(2x - 3)(2x+1)(2x-1)
2007-03-11 10:21:43 · answer #6 · answered by hbj 2 · 0⤊ 0⤋