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s = 1 or 2, since 4s+the carry must still be less than 10.

4t results in s in the units place, so s cannot be 1, so s=2.

therefore, t must be either 3 or 8, but 4s = 8, so t cannot be 3, so t=8

That means that p must be 1 or 2, since 4p doesn't generate a carry, but all the numbers are different, so p=1

so, we now have 21ar8x4 = 8ra12

4x8 =32, so the carry into the tens digit is 3, with resultant of 1, so 4r has 8 as the units digit, and must be either 2 or 7, but 2 is taken, so r=7

so, we now have 21a78x4 = 87a12, this last digit should be easy to figure out.

2007-03-11 10:00:52 · answer #1 · answered by arbiter007 6 · 2 0

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