6 men take 3 days to dig 8 ditches.
So 1 man can dig (8 / (3 x 6)) = 4/9 ditches per day.
Then 4 men can dig 4 x 4/9 = 16/9 ditches per day.
Finally, 10 / (16/9) = x.
x = 45 / 8 = 5 and 5/8 days. Rounded up it's 6 days.
2007-03-11 09:52:06
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answer #1
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answered by Anonymous
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First we assume that all men are able to work at the exact same rate. This means that we can solve a value (I'll call D) of units ditches per man day. This means, how many ditches can one man dig in one day. I'll set up a formula where di = ditches dug, m = men used and da = days taken.
D = di / (m * da)
D = 8 ditches / (6 man * 3 days)
D = 8 ditches / 18 man days
D = 8 / 18 = 4 / 9 ditches per man days
Now we can use the same formula to solve the second half of the problem.
D = di / (m * da)
4 / 9 = 10 / (4 * da)
16 / 90 = 1 / da
da = 90 / 16 = 45 / 8 = 5.625 days = 5.625 * 24 hours = 135 hours
2007-03-11 09:54:15
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answer #2
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answered by Tim 4
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Well I gave it a shot and figured that
3 days to do 8 ditches is 2+(2/3) ditches per day.
6 men to do 2+(2/3) ditches per day
so 1 man does 4/9 of a ditch in one day
working at equal rates, 4 men will do 16/9 ditch per day
you want 10 ditches so you need 5 days and 15 hours.
I hope someone gets the same answer as me.Good Luck with your class.
2007-03-11 10:04:32
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answer #3
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answered by Anonymous
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it takes (6*3)=18 man days to dig 8 ditches
now divide 18 by 8 to find how many man days per ditch:
18/8 = 2.25 man days per ditch
10 ditches will take 10 x 2.25 = 22.5 man days required
since you have 4 men working divide the man days by 4:
22.5/4 =5.625 or 5 5/8 days
2007-03-11 09:57:01
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answer #4
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answered by bignose68 4
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The amount of work is often counted in person-years or person-days.
Here, looks like person-days might be useful. One person working 10 days is the same as 10 persons working one day, or 5 persons working two days, etc. All these examples are 10 person-days.
8 ditches require 6 persons * 3 days = 18 person-days.
Then 10 ditches will require (10/8)*18 person days = 22.5 person-days of work.
you have 4 persons on the job so that they will have to work 22.5 / 4 = 5.625 days each.
2007-03-11 09:52:41
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answer #5
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answered by Raymond 7
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Okay, I think I may have it.
Take 8 ditches, and divide by 3 days to equal 2.667 ditches per day.
2.667divided by 6 men equal 0.4445 ditches per day EACH.
Then you start using your other numbers...
0.445 times 4 men equal 1.778 ditches per day
10 ditches divided by 1.778 ditches per day equals 5.6 days, which is your answer
I think this is the answer, but let me know if it's wrong.
2007-03-11 10:27:38
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answer #6
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answered by Anonymous
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6 people*3days = 18 people-days to dig 8 ditches
or 9/4 people-days per ditch
for 10 ditches, it will take 22.5 people-days
22.5 people-days/4people = 5.625 days
2007-03-11 09:55:01
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answer #7
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answered by jaybee 4
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6men X 3days (24hrs) = 8ditches
so that's 144 man hours = 8ditches
144/8 = hrs per ditch
10 ditches x hrs per ditch / 4 men
hope this helps you
2007-03-11 10:01:32
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answer #8
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answered by JB 1
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