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1.) use only the slope and the y-intercept to graph the following equation.
-3x + 2y= -2






2.) write the equation in standard form for each line for each line described.

passes through the point (0,1) and (2,0)
passes through (5,4) and is parallel to the line y= 1/5x - 2






3.) graph the equation y= -x square + 4x. use the vertex and four other points.








4.) find the range of the function.

H : b (arrow pointing right) b square -b -2 D= {0,2}

2007-03-11 09:09:50 · 2 answers · asked by Anonymous in Education & Reference Homework Help

okay, i already got number 1 out of the way. thank you.

2007-03-11 10:36:00 · update #1

2 answers

1)First you have to put the equation you're given in y=mx +b form. You wanna get the y by itself so you subtract positive 3x from both sides which gives you 2y=3x-2. Then you divide all your terms by 2 so the y will be completely by itself which fits the y=mx+b form. your final equation is now y=(3/2)x-1. The coefficient of x is the slope, (3/2). The y-int. is -1.
2)To get the slope you do (y2-y1)/(x2-x1). --->(0-1)/(2-0)= -1/2. using the slope u can put it into y=mx+b, then transfer it to the standard form.
Sorry I'm in algebra 2 and thats all i remember

2007-03-11 09:41:54 · answer #1 · answered by Goodmomma1 3 · 0 0

4678op=06

2007-03-11 16:13:34 · answer #2 · answered by david 2 · 0 0

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