here are some other algebra 1 problems i don't understand. please help, again!?

Question

1.) use only the slope and the y-intercept to graph the following equation.
-3x + 2y= -2






2.) write the equation in standard form for each line for each line described.

passes through the point (0,1) and (2,0)
passes through (5,4) and is parallel to the line y= 1/5x - 2






3.) graph the equation y= -x square + 4x. use the vertex and four other points.








4.) find the range of the function.

H : b (arrow pointing right) b square -b -2 D= {0,2}

okay, i already got number 1 out of the way. thank you.

Answer 1

1)First you have to put the equation you're given in y=mx +b form. You wanna get the y by itself so you subtract positive 3x from both sides which gives you 2y=3x-2. Then you divide all your terms by 2 so the y will be completely by itself which fits the y=mx+b form. your final equation is now y=(3/2)x-1. The coefficient of x is the slope, (3/2). The y-int. is -1.
2)To get the slope you do (y2-y1)/(x2-x1). --->(0-1)/(2-0)= -1/2. using the slope u can put it into y=mx+b, then transfer it to the standard form.
Sorry I'm in algebra 2 and thats all i remember

Answer 2

4678op=06