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i was absent for math for some time and well we are doing the surface areas of polgons and 3-d stuff and i'm getting confused because for every figure there is a different formula to solve them... like the surface area of pyramid, cube, cilinder and cones does anyone happen to know the different formulas for the volumes, surface areas and how to find base areas.

2007-03-11 08:54:14 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

Check this out, it may help!

http://math.about.com/library/blmeasurement.htm

2007-03-11 09:01:02 · answer #1 · answered by Anonymous · 0 0

It depends on what shape. For example, a cube's surface area would be the area of the base (length x width) times 6. For a cylinder, it would be the area of the circles times 2 and then l x w.

2007-03-11 08:58:15 · answer #2 · answered by Anonymous · 0 0

Cylinder: V= pi*r^2h ; S = 2pi*r^2 +2pi*rh =2pi*r(r+h)
Cone: V= (1/3)pi*r^2 h; S= pi*r*l + pi*r^2 [l= slant height]
Pyramid: V= (1/3)Bh; S = B+LA where B= base and LA = lateral area which depends on the shape of the base.
Sphere: V=(4/3)pi*r^3; S= 4pi*r^2
Cube: V = s^3 ; S =6s^2 where s is a side
Right Rectangular prism V= lwh S = 2(lw + lh+ wh)

2007-03-11 09:15:13 · answer #3 · answered by ironduke8159 7 · 0 0

Write down the formulas on a 4 x 6 card. Copy them out several times, so you have one which you tape by your mirror, one by your bed, one at the kitchen table or near where you eat your brekkie and din din.

Do as many problems as you can with each so you "internalize" it.

Don't fear. Don't panic. Breathe slowly, easily, fully, exhaling with each breath all the frustration, bad energy, worry, and other useless "waste." Breathe in oxygen, inspiration, blessings.

Face your solid geometry and other math as if it is a neighbour whom you finally have decided to get to know. Understand that this is a very interesting neighbour who might be a great friend or at least a helpful hand when you need her, or him.

Now get to work!

2007-03-11 08:59:48 · answer #4 · answered by Anonymous · 0 0

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