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Eleanor is phenotypically normal. Her husband, Garvey, has the X-linked dominant allele for brown-spotted teeth but otherwise is normal. Eleanor's brother, Arthur, and her son, Chester, both suffer from hemophilia (recessive bleeder's disease). Eleanor's father, Grandpa, is not a hemophiliac but is colorblind. Chester is also colorblind.

a) what are the genotypes of eleanor, garvey, chester and grandpa?
b) when eleanor realized that chester was colorblind as well as a hemophiliac she discovered what had happened to the oocyte that caused this. What happened to that oocyte?
c) What X-linked mutant gene or genes does Eleanor carry?
d) If Eleanor and Garvey have a daughter what's the probability it will be:
hemophiliac, then colorblind, then brown-toothed (each separately)
e) If they have a son what's the probability it will be:
hemophiliac, then colorblind, then brown-toothed (each separately)


also, how do i determine the ratios of G and O genes with a GgOo x ggoo box

2007-03-11 08:36:35 · 2 answers · asked by suggargurl302 2 in Science & Mathematics Biology

2 answers

Solve these big family history problems by drawing a pedigree. That's the only way to see what's going on.

Put the names and the genotypes by each person on the pedigree.

a. Eleanor is XtXt for tooth spots, XHXh for hemophilia, and XBXb for colorblindness.
Garvey is XTY for tooth spots, no other info on him
Chester is XtY for tooth spots, XhY for hemophilia, and XbY for colorblindness
Grandpa is XtY for tooth spots, no info for hemophilia (but we would assume not because Arthur got hemophilia from his mother on the X) and XbY for colorblindness

b. There must have been crossing over because the colorblind allele was on the X from her father and the hemophilia allele was on the X from her mother. They had to get onto the same X-chromosome to be passed on to Chester who only got one X from Eleanor.

c. Eleanor carries hemophilia and colorblindness, but on different X-chromosomes.

d. No chance of hemophilia because Garvey has the dominant normal allele on his XH.
No chance of colorblind because Garvey has the dominant normal allele on his XB.
100% chance of brown-toothed because Garvey has the dominant brown-toothed allele on his XT.

e. 50% chance of hemophilia because Eleanor has one X with an allele for hemophilia and the Y from Dad doesn't say.
50% chance for colorblind because Eleanor has one X with an allele for colorblind and the Y from Dad doesn't say.
0% chance for brown-toothed because Eleanor has no alleles for brown-toothed and the Y from Dad doesn't say.

I'm not sure what you're asking on the last one, but the gametes from parent GgOo are GO Go gO go. The gametes from parent ggoo are go go go go.

I really hope you are going to consider the explanations and try to understand the material rather than just writing down the answers. I know that AP classes have lots of homework and lots of material to cover, but I only answer these questions in order to explain and help kids learn.

2007-03-11 08:56:16 · answer #1 · answered by ecolink 7 · 0 0

A Taq polymerase is needed as that's a polymerase which could stand up to extreme temperatures, in comparison to maximum DNA polymerases. it rather is actual taken from an organism noted as Thermus aquaticus which could stand up to temperatures as extreme as a hundred seventy five F and actual thrive in that ecosystem. the only disadvantage is the the Taq polymerase isn't as committed in copying as different polymerases, so all people remains finding for a greater effective candidate polymerase.

2016-10-01 22:58:34 · answer #2 · answered by Anonymous · 0 0

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