2007-03-11 07:52:38 · 9 answers · asked by Anonymous in Computers & Internet ➔ Programming & Design
Eight hours a day with overtime expected. Calls at all hours of the night with problems. I was a programmer prior to cell phones and we always had to carry a beeper.
2007-03-11 07:55:26 · answer #1 · answered by Barkley Hound 7 · 0⤊ 0⤋
It depends on the level of the analyst. If you are working a helpdesk it is normally 8 am - 6 pm. If you are a project PC analyst hours depend on the project and this can be a 24 hour job. Senior support is on call 24 hours a day.
Hours are not a 9 - 5 in this feild of work..
2007-03-11 07:56:21 · answer #2 · answered by Trinisoccer 5 · 0⤊ 0⤋
Depends, if you are asking about a consultant, it is any time he gets a call, with extra for nigh time calls. But if you are talking about being hired by company 8 hours a day, on call 24-7-365. With overtime pay over 40 hours.
As a consultant you can not dewaddle all day. Business' expect to have there equipment up and running in an hour or two. If you are good, reall, really, good, a consultant can charge $180.00 on up.
2007-03-11 08:09:37 · answer #3 · answered by dick_bee_bad 5 · 0⤊ 0⤋
"regular computer analyst"? about 40 hrs/wk. This probably varies widely, but the greatest number are just regular working people.
2007-03-11 09:30:44 · answer #4 · answered by RPK 3 · 0⤊ 0⤋
24-7
2007-03-11 07:54:58 · answer #5 · answered by MrKnowItAll 3 · 0⤊ 0⤋
it depends on what type of work is done, dog. I've had 8-5 jobs and some that have you on call 24 hours
2007-03-11 07:56:22 · answer #6 · answered by leroy_w_jackson 3 · 0⤊ 0⤋
According to my link, they work about ~40 hours per week.
2007-03-11 07:56:05 · answer #7 · answered by pugfug90 2 · 0⤊ 0⤋
it depends..
network engineers (and analysts) are available and sometimes work 24x7x350+ days per year..
IT guys are available more along the 8x5
PC repair guys are also 8x5
2007-03-11 07:56:00 · answer #8 · answered by m34tba11 5 · 0⤊ 0⤋
PC like?
2007-03-11 07:54:32 · answer #9 · answered by stagger_lee1974 2 · 0⤊ 0⤋