Did I perform this Molarity calculation correctly?

Question

We are told to find the molarity of Cu2+ in solution B.

Solution B contains:
5mL copper iodate (aq)
1 ml en
Rest = Water to the calibration mark
Total V = 10mL

Should I do M1V1 = M2V2?

V1 = .005L
V2 = .0100L
M1 = Not Given
M2 = Not given.

Can I take grams of Cu(IO3)2 used and get moles. Put the moles of Liters to get Molarity, thus getting M1?

If so do I use the Liters of 5mL (its original volume) or the final 10mL?

Thanks

To find Molarity of 5mL aqueous copper iodate solution:

0.152g Cu(IO3)2 • 1 mol/460.926g Cu(IO3)2

= 0.000330 mol Cu(IO3)2

M = mol/L

M = 0.000330 mol Cu(IO3)2 / 0.005L

M = 0.0660

To find molar concentration of Cu2+ in Solution B:

M1V1 = M2V2
0.0660 M * 0.005 L = M2 * .010 L
M2 = 0.033

Answer 1

You can't solve this problem unless you know the concentration of Cu(IO3)2 exactly in the original solution.

Answer 2

Take the gram of copper iodate to get moles, N. This number of moles, N is dissolved in 10 ml of solution. The molarity, M is defined as the number of moles/1 liter. In this case, for v2 you should use the final 10ml.

Answer 3

hi! i'm actual examining chemistry AS point and have merely carried out AS module a million. Molarity (M) = concentration (dm3) this means that Molarity is named concentration besides!! so we are able to paintings out molarity by ability of understanding concentration. the formula for understanding concentration(Molarity) of a substance is concentration=moles/quantity (if the quantity is in cm3 you ought to divide by ability of one thousand to coach it into dm3) additionally, as we've a formula, we are able to additionally paintings out moles and quantity from this! e.g: moles=conc x vol vol= conc x mol There!! i'm hoping this has helped you If no longer, them deliver me teh question and that i will teach you a thank you to! gud luk!!