2x^2-11x+5=0?

Answer 1

2x² - 11x + 5

Find the sum of the middle term

Multiply 2 times 5 and factor

2 x 5 = 10

factors of 10 = 1, 2, 5, 10

- 10 and - 1 satisfy the sum of the middle term

2x² - 11x + 5

2x² - 1x - 10x + 5

x(2x - 1) - 5(2x - 1)

(x - 5)(2x - 1)

- - - - - - - - - - s-

Answer 2

2x^2-11x+5=0
(2x-1)(x-5)=0
2x-1=0; 2x=1; x=1/2
x-5=0; x=5

1/2,5

the easiest way to tell if a 2nd degree polynomial can be factored is to take the discrimant (b^2-4ac) and if it comes out to be a perfect square then it is factorable
in this case , a=2, b=-11, c=5
b^2-4ac = (-11)^2-4(2)(5)
121-40=81
81 is a perfect square (9^2) so it can be factored

Answer 3

look for two numbers that multiply to 10 and add to -11

-1 and -10

2x^2 - 1x - 10x + 5

factor by groups

(2x^2 - 1x) + (-10x + 5) = 0
x (2x - 1) + -5(2x - 1) = 0

(x - 5)(2x-1) = 0

x= 5 or 1/2