Is there a formula to it? Also i need help X^3-2x^2+4x-8
2007-03-11 07:49:22 · 4 answers · asked by Ballerina 5 in Science & Mathematics ➔ Mathematics
mathathesis whatever your name is your answer is wrong
2007-03-11 08:06:33 · update #1
(x+2)(10x^2+1)
For the second one: (x-2)(x^2+4)
2007-03-11 07:55:46 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
10x^3+20x^2+x+2
= 10x^2(x+2)+(x+2)
= (10x^2+1)(x+2)
x^3-2x^2+4x-8
= x^2(x-2)+2(x-2)
= (x^2+2)(x-2)
2007-03-11 14:53:53 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
factor the first two, then last two
10x^2(x+2) + 1(x+2)
notice how parenthesis are the same
(10x^2+1)(x+2)
2007-03-11 14:54:36 · answer #3 · answered by leo 6 · 0⤊ 0⤋
By inspection one of the roots is -2 Thus the expression can be written( x +2)( quadratic) etc
2007-03-11 14:56:19 · answer #4 · answered by physicist 4 · 0⤊ 0⤋