2007-03-11 07:43:14 · 5 answers · asked by help_me 1 in Science & Mathematics ➔ Mathematics
Did you write the problem down right? As it is now..
simply x^2-8+4 to x^2-4..
Isolate the variable..
x^2=4
Take the square root..
x= (+/-) 2
x=-2, 2
2007-03-11 07:49:11 · answer #1 · answered by pugfug90 2 · 0⤊ 0⤋
X = + or - 2
2007-03-11 07:46:20 · answer #2 · answered by physicist 4 · 0⤊ 0⤋
x² - 8 + 4 = 0
x² - 4 = 0
x² - 4 + 4 = 0 + 4
x² = 4
√x² = ± √4
x = ± 2
- - - - - -
Check for +
x² - 8 + 4 = 0
(2)² - 8 + 4
4 - 8 + 4 = 0
-4 + 4 = 0
0 = 0
- - - - - - -
Check for -
x² - 8 + 4 + 0
( - 2)² - 8 + 4 = 0
4 - 8 + 4 = 0
- 4 + 4 = 0
0 = 0
- - - - - - s-
2007-03-11 08:20:25 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
X= 2
1:add like terms: x^2-4=o
2:distribute: x*x=4
3: find number that when squared equals 4 : x=2
2007-03-11 07:47:33 · answer #4 · answered by prnszcrtny 3 · 0⤊ 0⤋
x^2-12=0
x^2=12
x=+-sqrt(12)
If that -8 should have been -8x, then
x^2-8x+4=0
using quadratic formula
x=0.54 or x=7.46
2007-03-11 07:47:41 · answer #5 · answered by leo 6 · 0⤊ 0⤋