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2007-03-11 07:05:57 · 2 answers · asked by Iryna 2 in Science & Mathematics Chemistry

2 answers

C6H4(OH)CO2H

2007-03-11 07:08:58 · answer #1 · answered by Anonymous · 0 1

2-hydroxy benzoic acid.

2007-03-11 14:24:01 · answer #2 · answered by Gervald F 7 · 0 0

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