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3 answers

The first example on the source page listed below answers your question.

2007-03-12 10:49:27 · answer #1 · answered by Jim R 3 · 0 0

that's least perplexing to apply the certainty that a function is non-end if and on condition that inverse photographs of closed gadgets are closed. So enable C be closed in Y. The inverse image of C under h is the union of the inverse photographs of C under f and g. yet those are the two closed subsets of closed subspaces, so are closed in X. yet then the union is closed in X.

2017-01-04 07:13:44 · answer #2 · answered by Anonymous · 0 0

That's way to hard for us, maybe you simplify it..

2007-03-11 08:51:45 · answer #3 · answered by Anonymous · 0 0

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