What two numbers when multiplied give you -128. Those same numbers give you -1 when added together.?

Question

When multiplied you get -128.
When added you get -1
What are the two numbers...

sorry to waste peoples time but i was trying to factor an equation and the equation is 8x+-x^2+-16 and i had it in the wrong order...it is supposed to be -x^2+8x+-16...so it isnt -128 its 16 and the numbers would be 4 and 4 added =8 and multiplyed =16

so yeah i did it wrong....sorry for wasting your time =) have a nice day!

Answer 1

The original question had an answer though. Someone above had it right. It's 10.825 and -11.825.

Answer 2

ok. we've 2 numbers, call them x and y all of us understand that their product is -fifty six. So: x * y = -fifty six We additionally understand that an identical 2 numbers further mutually equivalent 2. So: x + y = 2 Subtract y from the two factors interior the 2d equation. we are left with: x = 2 - y Plug this in for x into our first equation. So we've: (2 -y) * (y) = -fifty six Multiplying by way of we get: 2y - y^2 = -fifty six that's comparable to: y^2 - 2y - fifty six = 0 making use of the quadratic formula we've: y = (2 +/- sqrt(4 + 4 *fifty six)) / 2 = (2 +/- sqrt (228) ) / 2 = a million +/- sqrt(fifty seven) meaning: y = a million + sqrt(fifty seven) OR y = a million - sqrt(fifty seven) If y = a million + sqrt(fifty seven) , we plug this back into our equation that pronounced x + y = 2 x + a million + sqrt(fifty seven) = 2 Subtracting the a million and the sqrt(fifty seven), we've: x = a million - sqrt(fifty seven) If y = a million - sqrt(fifty seven), following an identical steps we've: x= a million + sqrt(fifty seven) those are our 2 recommendations. **************************************... those appear as if very complicated solutions, are you specific an identical 2 numbers further mutually do no longer equivalent a million? in the event that they do, then we'd have: y^2 - y -fifty six = 0 as a replace of y^2 - 2y - fifty six = 0 y^2 - y - fifty six = 0 may be factored as: (y - 8) * (y + 7) = 0 which might provide us recommendations: y = 8 OR y = -7 Plugging those back into our equation x + y = a million while y = 8: x + 8 = a million Subtracting 8 from the two factors we've: x = -7 while y = -7 x - 7 = a million including 7 to the two factors we've: x = 8 **************************************...

Answer 3

number 1 = a
number 2 = b

a+b = -1
so a = -b-1 = -(b+1)

a x b = -128
-(b+1) x b = -128
(b+1) x b -128 = 0
b^2 + b -128 = 0
using quadratic formula:
[-1 +- sqrt(1^2 - 4 x 1 x -128)] / (2x1)
= [-1 +- sqrt(513)] / 2

=10.825... and -11.825...

These are the two numbers

Answer 4

There is no solution that includes integers. It sounds like you are doing factoring with quadratic equations, so I recommend using completing the square or using the quadratic formula.

X = -b(+ or -)(the square root of b^2-4ac)
all divided by 2a

Answer 5

Thanks for taking the trouble to say you'd made a mistake - most people would have just left it.

Answer 6

well its not whole numbers?