√20/5 -1/√5
√20=√(4*5)=2√5
2√5/5 -1/√5
=2/√5 -1/√5
=1/√5 *(√5/√5)--(rationalize)
=√5/5
2007-03-11 04:42:30
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answer #1
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answered by Maths Rocks 4
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step 1: put it all over a common factor
to do this you have to multiply 1/sqrt(5) top and bottom by sqrt(5) to give:
sqrt(5) / 5
then you can add the terms together to get
[sqrt(20) - sqrt(5)] / 5
Step 2: expand and simplify the numerator
sqrt(20) = sqrt(4) x sqrt(5)
= 2 x sqrt(5)
so now we have [2 x sqrt(5) - sqrt(5)] / 5
= sqrt(5) / 5
Step3: cancel down the fraction
5 = sqrt(5) x sqrt(5)
so we get
sqrt(5) / [sqrt(5) x sqrt(5)]
= 1 / sqrt(5)
so your answer is
sqrt(5) / 5 or 1 / sqrt(5)
depending on whether you want a rational denominator
2007-03-11 11:48:24
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answer #2
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answered by rg 3
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I assume this is (sqrt20/5) -1/sqrt(5)
put over a common denominator by cross multiplying:
(sqrt20(sqrt(5) -5)/ 5sqrt(5)
you can factor sqrt5 from first term:
((sqrt(4)sqrt(5)(sqrt(5) -5)/5sqrt5
now substitute 2 for the sqrt 4 and 5 for sqrt(5)(sqrt(5):
(2(5) -5)/5sqrt5 = 1/sqrt(5)
2007-03-11 11:46:28
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answer #3
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answered by bignose68 4
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You have to multiply the second section section by (sqrt5)/(sqrt5). That's the way to get rid of sqrt in denominator. So that will be (1/sqrt5)*(sqrt5/sqrt5). 1*sqrt5 = sqrt 5, and sqrt5*sqrt5 = 5.
So now you have (sqrt20)/5 - (sqrt5/5). Sqrt20 can be factored down to (2*sqrt5). Then just add 2*sqrt5 + sqrt5 = 3*sqrt5. Divide that by the 5 on the bottom.
Final answer is (3*sqrt5)/(5)
2007-03-11 11:46:50
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answer #4
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answered by doctorevil64 4
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The problem is not well defined.
[(20/5)^0.5 - 1] / 5^0.5 is one way of writing what you wrote.
That would be 4^0.5 - 1 = 3-1 = 2 divided by sqrt.5
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But if we write (sqrt.20 / 5) - (1/sqrt.5) we can write it as:
sqrt.20 = sqrt. 4X5 = 2 sqrt.5 and this divided by 5 gives
2/sqrt.5 and then we have
2/sqrt.5 - 1/sqrt.5 = 1/sqrt.5
This appears to be more reasonable.
2007-03-11 11:46:15
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answer #5
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answered by Swamy 7
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sqrt(20)/5-1/sqrt(5)
=sqrt(20/25)-1/sqrt(5)
=sqrt(4/5)-1/sqrt(5)
=sqrt(4)/sqrt(5)-1/sqrt(5)
=2-1/sqrt(5)
=1/sqrt(5)
that is approximately equal to 0.447215
2007-03-11 11:49:58
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answer #6
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answered by satwik 2
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â20/5 - 1/â5
= â(4 x 5) / 5 - â5 / 5
= 2.â5 / 5 - â5 / 5
= (1/5).(2â5 - V5)
= (1/5).â5
2007-03-11 11:53:40
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answer #7
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answered by Como 7
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sqrt20/(5 -1/sqrt5) = sqrt 20 sqrt5/(sqrt5 - 1) = sqrt100/(sqrt5 - 1) = 10/ (sqrt5 - 1) = 5/2 (sqrt5 +1)
2007-03-11 11:43:29
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answer #8
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answered by physicist 4
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