Multiply two polynomials?

Question

(y+8) (y+3)=

and

(a+2) (a^2- 3a+7)=

Answer 1

Even though the other ppl gave you the answers, it would probably be helful for you to know how to do the problems.

For the first one, use the FOIL method (First, Outer, Inner, Last). Multiply the first things in the parentheses: y x y is y^2. Then do the outer ones: y x 3= 3y. Next is inner: 8 x y = 8y. Then last: 8 x 3= 24. Writing all that out on one line would give you y^2 + 3y + 8y + 24. Add like terms to simplify the equation: y^2 + 11y + 24. That's your answer.

For the second one, just distribute the a through the other set, and then go back and distribute the 2 through the other set. Add like terms to simplify, and you should get your equation. Because you have an "a" times an "a^2," you should have an "a^3" somewhere in the final equation---that's just a good check for yourself when you get the answer.

Answer 2

Question 1
= y² + 3y + 8y + 24
= y² + 11y + 24

Question 2
= a³ - 3a² + 7a + 2a² - 6a + 14
= a³ - a² + a + 14

Answer 3

ok for the first answer you have
(y+8)(y+3)
1: multiply y by y = y^2
2: multiply y by 3= 3y
3: multiply 8 by y = 8y
4: multiply 8 by 3= 24
(you have to multiply ever monomial in the parenthesis by ever monomial in the second parenthesis)
5: combine like terms (3y and 8y)= 11y
5 your answer is y^2+ 11y+ 24

for the question (a+2)(a^2-3a+7)
1: multiply a by a^2= a^3
2: multiply a bye -3a= -3a^2
3: multiply a by 7= 7a
4: muliply 2 by a^2= 2a^2
5: multiply 2 by -3a= -6a
6: multiply 2 by 7= 14
7: add like terms (-3a^2 and 2a^2)= -a^2
8: add other like terms (7a and -6a)= a
9: your answer is a^3-a^2+a+14

Answer 4

= y^2 + 11y + 24


= a^3 - 3a^2 + 7a + 2a^2 - 6a + 17
= a^3 - a^2 + a +17

Answer 5

y^2 +11y +24


a^3 -3a^2 +7a +2a^2 - 6a +14 =
a^3 - a^2 + a +14

Answer 6

The first one is y^2+11y+24.
The second one is a^3-a^2+a+14.

Answer 7

1)*y&y
2)*first y with 3
3)muliply 8 with the second y
3)muliply the 8 with 3
FOIL-first, outer, inner,last

do the same on the second problem
first multiply the a with all the numbers in the second ()
second multiply the 2 in the second ()

oh i forgot combine like terms

Answer 8

first
y*y+8*y+3*y+3*8
=y^2+11y+24

second

a*a^2+2*a^2-a*3a-2*3a+7*a+7*2
=a^3+2a^2-3a^2-6a+7a+14
=a^3-a^2+a+14
is it OK!!!!!!!!!!

Answer 9

The above answers are correct but you need to know how they are derived.

(a+b)(c+d)=ac+ad+bc+bd

(a+b)(c+d+e)=ac+ad+ae+bc+bd+be