2007-03-11 04:16:56 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5x^7y^8*6xy^3/(3x^2y)
=5*6/3* x^(7+1-2)*y^(8+3-1)
=10x^6*y^10
2007-03-11 04:22:51 · answer #1 · answered by san 3 · 0⤊ 0⤋
5x^7 × 7y^8 × 6xy^3/3x^2y
=5 × 6 x^7×x^1 × y^8 × y^3 / 3x^2y
= 30 x^8 × y^11 / 3x^2y
=(30/3) x^8 × x^(–2) y^11y^(–1)
= 10 x^6 × y^10
= 10 x^6 y^10
2007-03-11 05:03:22 · answer #2 · answered by Pranil 7 · 0⤊ 0⤋
4x - (2 - 3x) + 5 To simplify this equation, first take the parentheses out of the equation by technique of creating use of the distributive sources. The distributive sources states for any numbers a, b, and c: a(b + c) = ab + ac on your equation, there is not any determination in the front of the parentheses, yet there's a subtraction signal before them. whenever you spot a subtraction signal before the parentheses, then change the addition and subtraction signs and indications interior to the different signal and eliminate the parentheses: 4x - (2 - 3x) + 5 4x - 2 + 3x + 5 <=== signs and indications switched Now combine like words: 7x - 2 + 5 Subtract 2 from 5: 7x - 3 that is your answer. wish this helped!
2016-12-01 20:09:50 · answer #3 · answered by ? 4 · 0⤊ 0⤋
= 30 x^(8) y^(11) / 3 x² y
= 10 x^(6) y^(10)
2007-03-11 04:34:57 · answer #4 · answered by Como 7 · 0⤊ 0⤋
= (5x^6y^10)/3
2007-03-11 04:22:16 · answer #5 · answered by physicist 4 · 0⤊ 0⤋
NO YOU CAN NOT
2007-03-11 04:19:55 · answer #6 · answered by Anonymous · 0⤊ 0⤋