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Let x represent the number.
6 times a number is 14 more than that number.

My choices are:
a) 6x +14=x
b) 6=14x + x
c) 6x=x =14
d) 6x = 14x
Everytime I do this I come up with a different answer. Help !!

2007-03-11 04:07:00 · 8 answers · asked by barbjs45 1 in Science & Mathematics Mathematics

8 answers

Shouldn't the answer be this:
6x=14+x or this
6x=x+14

I hope this helps!

2007-03-11 04:12:44 · answer #1 · answered by Anonymous · 4 0

6x = 14 - x

6 times 2 is 14 more than 2.

I can also solve it for you.

6x + x = 14

7x = 14

x = 14 / 7

x = 2

Now, substitute it for x.

6(2) = 14 - 2

12 = 12

Now, the statement becomes:

6 times 2 is 14 more than 2.

2007-03-11 04:16:07 · answer #2 · answered by Anonymous · 0 0

The answer is not c) becaues it says 6 times a # equals a # equals 14.
The answer is not d) because it says 6 times a # equals 14 times that #.
The answer is not a). The answer is not b). The answer is 6x=14+x.
I do not know what x is equal to.

2007-03-11 05:26:46 · answer #3 · answered by Jessica 4 · 0 0

Let x represent the number.

x

6 times a number

6x

is 14 more than that number

6x = x + 14

what is the problem ?

2007-03-11 05:12:45 · answer #4 · answered by gjmb1960 7 · 0 0

"9 below 17 cases a range" Take 17 cases the determination, then subtract 9. 17x - 9 "is" interprets to "=" "5 cases that particular same determination" ability 5x. placed all of it jointly, and also you get 17x - 9 = 5x Going a step added, you are able to particularly clean up this. 17x - 9 = 5x 12x - 9 = 0 12x = 9 x = 9/12 = 3/4

2016-12-01 20:09:27 · answer #5 · answered by ? 4 · 0 0

6x = x + 14 is the correct answer.which does not appear in your list unless there's an error in c) and the last "=" is in fact a "+" . !

2007-03-11 04:12:33 · answer #6 · answered by physicist 4 · 2 0

6x=x+14
1:move x to the left which gives you 5x=14
2: divide by 5 which gives you x= 2.8

2007-03-11 05:21:47 · answer #7 · answered by prnszcrtny 3 · 0 0

i think its 6x=x+14

2007-03-11 04:25:47 · answer #8 · answered by Ana C 3 · 0 0

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