A building with height D shadow upto G. What is the height of a neighbouring building with a shadow of C feet.

Answer 1

Since the two buildings neighbour each other and the light source (the Sun/Moon -> assumption) is infinite, their shadows will fall at similar angles, and the resulting triangles will therefore also be similar.

The lengths of the corresponding sides of two similar triangles are proportional to each other. In other words,

D/G = X/C, where X is the height of the 2nd building.

X = (D/G)*C

[Like the earlier answer said]

Answer 2

There isn't much informaiton to work with - and the first part of the quesiton doesn't actually give you any information you can use, perhaps you've typed something wrong?

Anyway, using the sine ratio you could say that the height = C * Sin (Theta) where theta is the angle of elevation from the ground to the top of the building of height h

Answer 3

Depends on the height of C, the distance between D and C, the direction of light, Is it a mathetical question ?
Or G.Mental ability question, if it that then answer is F
D EF G
C DE F

Answer 4

Pythagorean theorem. Square on the Hypotenuse is equal to the sum of the squares on the other two sides. Shadow is hypotenuse.

Answer 5

Dave has the correct approach.

Using ratio and proportion one can get the answer with minimum calculations.

So you do not need more info.

Answer 6

D/G = x/C

Solve for x.

You can rewrite the problem:

x = (D*C)/G

Answer 7

Answer is = (C/G) * D feet

Answer 8

[D/(G-D)]*C