z = x/y
2007-03-11 03:23:01 · 4 answers · asked by rwtire2002 2 in Science & Mathematics ➔ Mathematics
First set f(x, y) = x/y
calculate df/dx = 1/y and df/dy = -x/y^2
Now put each into the following formula:
dz = (df/dx) dx + (df/dy) dy
= (1/y) dx - (x/y^2) dy
.
2007-03-11 03:27:58 · answer #1 · answered by Ken M 3 · 1⤊ 0⤋
Differentiate with respect to x using z = x.y^(-1)
dz/dx = 1.y^(-1) - x.y^(-2).dy/dx
multiplying by dx gives:
dz = 1/y.dx - (x/y²).dy
This can, of course, be done directly too.
2007-03-11 03:29:26 · answer #2 · answered by sumzrfun 3 · 0⤊ 0⤋
dz = (1/y)dx + (-x/y^2)dy
using dz = (df/dx)suby dx + (df/dy)subx dy
sub x and sub y meann with y and x const. ie they are partial derivatives ..
2007-03-11 03:38:08 · answer #3 · answered by physicist 4 · 0⤊ 0⤋
dz= 1/y*dx-x/y^2 *dy
2007-03-11 03:36:58 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋