step 1: set equation to "y"-->5x+2y = -23
-move "5x" to the other side by substracting
-get "y" by itself, divide by 2 on both sides
y=(-23/2)-(5x/2)
2x+y=-10
-get "y" by itself, substract "2x"
y=-10-2x
step 2: put the 2 equations into calculator
step 3: find the intersecting points
answer: (-3, -4)
2007-03-11 03:19:32
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answer #1
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answered by shih rips 6
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To solve this by graphing, you need graph paper.
Set y = 0 in the first equation, that gives you:
5x = 23 or x=23/5 or x= 4 + 3/5. Mark this on your horizontal (x-axis).
Set x = 0 in the first equation, that gives you:
2y=23 or y = 23/2 or y = 11 + 1/2. Mark this on your vertical (y-axis).
Draw a straight line between the points.
Now do the same thing on the second equation to give you a line representing the second equation. You now have the intersection which is the solution for x and y.
2007-03-11 03:20:44
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answer #2
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answered by Skeptic 7
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you gotta be kidding me, how can we put the graph in here?
anyway, i got some answer using formulas... not by graphing although i have the graph solution i just cant put it here. :/
Solution:
5x + 2y = -23
2x + y = -10
solving for x;
2x + y = -10
y = -10 - 2x
so,
5x + 2(-10 - 2x) = -23
5x - 20 - 4x = -23
x - 20 = -23
x = 20 - 23
x = -3
substituting x = -3
y = 10 - 2x
y = -10 - 2(-3)
y = -10 + 6
y = -4
2007-03-11 03:34:20
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answer #3
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answered by shadcode 2
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The intersection of these two linear functions is:
x = -3
y = -4
I used Mathcad 2000 to do a graphical solution, as required. Unfortunately, I am unable to import the graph into Answers. Suggest you substitute various integers for x and solve for each corresponding value of y. Do this for both equations and plot your results. At least you now know where the two straight lines will intersect......
2007-03-11 03:43:05
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answer #4
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answered by Diogenes 7
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This is called 'solving simultaneous equations using graphs'.
I think I can help you out....
http://www.bbc.co.uk/schools/gcsebitesize/maths/algebrah/graphsrev2.shtml
The point where the lines cross is your answer (a co-ordinate).
2007-03-11 03:29:49
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answer #5
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answered by ellietricitycat 4
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