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2007-03-11 03:03:23 · answer #1 · answered by maussy 7 · 0 0

you would set the data from least to greatest....then you would try to find the median,,,......ok just look below okay..
use this data 3,7,9,14,16,19,19,25,28 the median is16....Q1 is 8 and q3 is 22....because 16 is in the middle....and on the left 7 and 9 is in the middle so u would add 7+9 then divided by 2 and get your answer then do it for the other side for Q3

2007-03-12 13:25:39 · answer #2 · answered by Sexxi Nera 1 · 0 0

hi this is complication-free once you be attentive to :) you have sixteen documents First quartile ; divide sixteen by ability of four ==> 4 the 1st quartile is the information correspounding to the N°4 ==> sixty two If it replaced into no longer 4 yet 4.25 or 4.seventy 5, you may take the 5th 0.33 quartile : divide by ability of four and multiply by ability of three : sixteen * 3/4 = 12 around quantity. you're taking the N° 12 ==> 89 First quartile sixty two 0.33 quartile 89 you notice it is trouble-free Bye !

2016-12-14 16:15:55 · answer #3 · answered by ? 4 · 0 0

Log on to peltiertech.com/Excel/Charts/BoxWhisker.html

2007-03-11 03:02:16 · answer #4 · answered by BARROWMAN 6 · 0 0

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