Counting Principle, combinations of words?

Question

Counting principle?

i have the words ELODM and OCTUN
i have to find: how many ways are there to arrange the letters in each of the first two scrambled words
and the second question is unscramble each of the words. how many ways are there to arrange these letters
aren't these two questions the same?

Answer 1

You have to be very good in english vocabulary to answer second question.

1) there are 5 places and 5 words
1st position 5 options
2nd position 4 options
3rd position 3 options
4th position 2 options and finally 5th position one option

multiply the numbers 5X4X3X2X1 = 120

Q2: as far as my English vocabulary is concerned, MODEL and COUNT are the answer.

Answer 2

There are 5 different letters in the first group. Therefore this group of letters can be arranged in 5! = 5x4x3x2 = 120 ways.

The answer is the same for the second group, as the letters are again all different within that group.

The words are MODEL and COUNT.

The last question may be asking you to find how many different words can be formed from each group. I can see only one word in each case.

Answer 3

Whoever said 50 ways is quite mistaken. In each word the letters are all different, therefore the number of combinations is 5 factorial or "5!" which equals 1*2*3*4*5 = 120 ways for each combination of 5 letters.

Answer 4

this principle in math is called PERMUTATION.
the concept is to count how many ways a number of objects could be arranged. and it is translated mathematically as (n)!
this is read "n factorial".
to solve for a factorial, you basically, multiply n(n-1)(n-2)(n-3)...(n-n), where n is the number of objects you are to arrange.

to answer your question :

n=5
5! = 5(4)(3)(2)(1) =120

Answer 5

1)There are 50 ways of arranging them by different orders.
2)No, they are not same questions. You have to find meaningful words to answer second question. MODEL And COUNT

Answer 6

1) model
count

2) model
count

Answer 7

model and count